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x^2+4x-0.9=0
a = 1; b = 4; c = -0.9;
Δ = b2-4ac
Δ = 42-4·1·(-0.9)
Δ = 19.6
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-\sqrt{19.6}}{2*1}=\frac{-4-\sqrt{19.6}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+\sqrt{19.6}}{2*1}=\frac{-4+\sqrt{19.6}}{2} $
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